x^2+3x+5=2

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Solution for x^2+3x+5=2 equation:


Simplifying
x2 + 3x + 5 = 2

Reorder the terms:
5 + 3x + x2 = 2

Solving
5 + 3x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
5 + -2 + 3x + x2 = 2 + -2

Combine like terms: 5 + -2 = 3
3 + 3x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
3 + 3x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-3' to each side of the equation.
3 + 3x + -3 + x2 = 0 + -3

Reorder the terms:
3 + -3 + 3x + x2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 3x + x2 = 0 + -3
3x + x2 = 0 + -3

Combine like terms: 0 + -3 = -3
3x + x2 = -3

The x term is 3x.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3x + 2.25 + x2 = -3 + 2.25

Reorder the terms:
2.25 + 3x + x2 = -3 + 2.25

Combine like terms: -3 + 2.25 = -0.75
2.25 + 3x + x2 = -0.75

Factor a perfect square on the left side:
(x + 1.5)(x + 1.5) = -0.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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